Introduction

In this blog post, we will explore how to solve the LeetCode problem "1793" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an array of integers nums (0-indexed) and an integer k. The score of a subarray (i, j) is defined as min(nums[i], nums[i+1], ..., nums[j]) (j - i + 1). A good subarray is a subarray where i <= k <= j. Return the maximum possible score of a good subarray. Example 1: Input: nums = [1,4,3,7,4,5], k = 3 Output: 15 Explanation: The optimal subarray is (1, 5) with a score of min(4,3,7,4,5) (5-1+1) = 3 5 = 15. Example 2: Input: nums = [5,5,4,5,4,1,1,1], k = 0 Output: 20 Explanation: The optimal subarray is (0, 4) with a score of min(5,5,4,5,4) (4-0+1) = 4 5 = 20. Constraints: 1 <= nums.length <= 105 1 <= nums[i] <= 2 104 0 <= k < nums.length

Explanation

• Sliding Window Expansion: Start with a window centered at index k and expand it outwards.
  • Maintain Minimum: Keep track of the minimum value within the current window.
  • Update Maximum Score: Update the maximum score as the window expands, calculating the score based on the current minimum and window size.

• Runtime Complexity: O(n), where n is the length of the input array. Storage Complexity: O(1).

Code

    def maximumScore(nums, k):
    n = len(nums)
    left = k
    right = k
    min_val = nums[k]
    max_score = nums[k]

    while left > 0 or right < n - 1:
        if left == 0:
            right += 1
        elif right == n - 1:
            left -= 1
        elif nums[left - 1] < nums[right + 1]:
            right += 1
        else:
            left -= 1

        min_val = min(min_val, nums[left], nums[right])
        max_score = max(max_score, min_val * (right - left + 1))

    return max_score