Introduction

In this blog post, we will explore how to solve the LeetCode problem "1200" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements. Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows a, b are from arr a < b b - a equals to the minimum absolute difference of any two elements in arr Example 1: Input: arr = [4,2,1,3] Output: [[1,2],[2,3],[3,4]] Explanation: The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order. Example 2: Input: arr = [1,3,6,10,15] Output: [[1,3]] Example 3: Input: arr = [3,8,-10,23,19,-4,-14,27] Output: [[-14,-10],[19,23],[23,27]] Constraints: 2 <= arr.length <= 105 -106 <= arr[i] <= 106

Explanation

Here's the breakdown of the approach, complexities, and the Python code:

• Sort the array: Sorting allows us to efficiently compare adjacent elements to find the minimum absolute difference.
• Find the minimum difference: Iterate through the sorted array, calculating the difference between adjacent elements and updating the minimum difference found so far.

• Collect pairs with the minimum difference: Iterate through the sorted array again, and add pairs of adjacent elements whose difference equals the minimum difference to the result list.

• Runtime Complexity: O(n log n), dominated by the sorting step. Storage Complexity: O(n), primarily due to the space used for sorting (in-place sorts can reduce this).

Code

    def minimumAbsDifference(arr):
    """
    Finds all pairs of elements with the minimum absolute difference of any two elements.

    Args:
        arr: A list of distinct integers.

    Returns:
        A list of pairs in ascending order, each pair [a, b] follows:
        - a, b are from arr
        - a < b
        - b - a equals to the minimum absolute difference of any two elements in arr
    """

    arr.sort()
    min_diff = float('inf')

    # Find the minimum absolute difference
    for i in range(len(arr) - 1):
        min_diff = min(min_diff, arr[i+1] - arr[i])

    result = []
    # Collect pairs with the minimum absolute difference
    for i in range(len(arr) - 1):
        if arr[i+1] - arr[i] == min_diff:
            result.append([arr[i], arr[i+1]])

    return result