Introduction

In this blog post, we will explore how to solve the LeetCode problem "3133" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given two integers n and x. You have to construct an array of positive integers nums of size n where for every 0 <= i < n - 1, nums[i + 1] is greater than nums[i], and the result of the bitwise AND operation between all elements of nums is x. Return the minimum possible value of nums[n - 1]. Example 1: Input: n = 3, x = 4 Output: 6 Explanation: nums can be [4,5,6] and its last element is 6. Example 2: Input: n = 2, x = 7 Output: 15 Explanation: nums can be [7,15] and its last element is 15. Constraints: 1 <= n, x <= 108

Explanation

Here's the breakdown of the solution:

• Understanding the AND constraint: All numbers in the array must have x as a common bitwise AND result. This means x must be a subset of the bits present in every number in nums. Therefore, every number in nums must have all the bits set in x.

• Minimizing the last element: To minimize nums[n-1], we must minimize all the preceding elements. We start with x as the first element, which is the smallest possible value that satisfies the bitwise AND condition. Then, to make each subsequent element greater than the previous and still keep x as their bitwise AND, we simply increment by 1. This results in the sequence x, x+1, x+2, ..., x+n-1. Thus, the last element would be x + n - 1.

• Runtime & Storage Complexity: O(1) runtime, O(1) storage.

Code

    def solve():
    n, x = map(int, input().split())
    print(x + n - 1)

solve()