Introduction

In this blog post, we will explore how to solve the LeetCode problem "1848" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an integer array nums (0-indexed) and two integers target and start, find an index i such that nums[i] == target and abs(i - start) is minimized. Note that abs(x) is the absolute value of x. Return abs(i - start). It is guaranteed that target exists in nums. Example 1: Input: nums = [1,2,3,4,5], target = 5, start = 3 Output: 1 Explanation: nums[4] = 5 is the only value equal to target, so the answer is abs(4 - 3) = 1. Example 2: Input: nums = [1], target = 1, start = 0 Output: 0 Explanation: nums[0] = 1 is the only value equal to target, so the answer is abs(0 - 0) = 0. Example 3: Input: nums = [1,1,1,1,1,1,1,1,1,1], target = 1, start = 0 Output: 0 Explanation: Every value of nums is 1, but nums[0] minimizes abs(i - start), which is abs(0 - 0) = 0. Constraints: 1 <= nums.length <= 1000 1 <= nums[i] <= 104 0 <= start < nums.length target is in nums.

Explanation

Here's the solution to find the index i such that nums[i] == target and abs(i - start) is minimized:

• Iterate through the array: Go through each element of the nums array along with its index.
• Check for target: If the current element matches the target, calculate the absolute difference between the current index and start.

• Minimize the difference: Keep track of the minimum absolute difference found so far and update it whenever a smaller difference is encountered.

• Runtime Complexity: O(n), where n is the length of the nums array. Storage Complexity: O(1).

Code

    def getMinDistance(nums, target, start):
    """
    Finds the minimum absolute distance between the start index and an index i
    where nums[i] == target.

    Args:
        nums: A list of integers.
        target: The target integer to find.
        start: The starting index.

    Returns:
        The minimum absolute distance.
    """
    min_distance = float('inf')  # Initialize with a large value
    for i in range(len(nums)):
        if nums[i] == target:
            distance = abs(i - start)
            min_distance = min(min_distance, distance)

    return min_distance