# Solving Leetcode Interviews in Seconds with AI: Minimum Element After Replacement With Digit Sum


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "3300" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given an integer array nums. You replace each element in nums with the sum of its digits. Return the minimum element in nums after all replacements.   Example 1:  Input: nums = [10,12,13,14] Output: 1 Explanation: nums becomes [1, 3, 4, 5] after all replacements, with minimum element 1.  Example 2:  Input: nums = [1,2,3,4] Output: 1 Explanation: nums becomes [1, 2, 3, 4] after all replacements, with minimum element 1.  Example 3:  Input: nums = [999,19,199] Output: 10 Explanation: nums becomes [27, 10, 19] after all replacements, with minimum element 10.    Constraints:  1 <= nums.length <= 100 1 <= nums[i] <= 104  

	# Explanation
	Here's the solution to the problem, focusing on efficiency:

*   **Digit Sum Calculation:** Efficiently calculate the digit sum for each number by iteratively extracting digits using the modulo operator (%) and integer division (//).
*   **Finding Minimum:**  Iterate through the transformed array to find the minimum element.

*   **Time and Space Complexity:** O(N * log(M)), where N is the number of elements in `nums` and M is the maximum value of the elements (due to the digit sum calculation). Space Complexity: O(1) - constant extra space.

	
	# Code
	```python
	def digit_sum(n):
    sum_digits = 0
    while n > 0:
        sum_digits += n % 10
        n //= 10
    return sum_digits

def minimum_digit_sum(nums):
    """
    Replaces each element in nums with the sum of its digits and returns the minimum element.
    """
    min_val = float('inf')
    for num in nums:
        digit_sum_val = digit_sum(num)
        min_val = min(min_val, digit_sum_val)
    return min_val
	```