Introduction

In this blog post, we will explore how to solve the LeetCode problem "453" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an integer array nums of size n, return the minimum number of moves required to make all array elements equal. In one move, you can increment n - 1 elements of the array by 1. Example 1: Input: nums = [1,2,3] Output: 3 Explanation: Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4] Example 2: Input: nums = [1,1,1] Output: 0 Constraints: n == nums.length 1 <= nums.length <= 105 -109 <= nums[i] <= 109 The answer is guaranteed to fit in a 32-bit integer.

Explanation

Here's the approach to solve this problem:

• Key Insight: Incrementing n - 1 elements is equivalent to decrementing one element. The goal is to bring all elements to the same value. Therefore, we can think of it as decrementing the larger elements towards the smallest element.
• Finding the Minimum: The target value all elements should reach is the minimum element in the array.

• Calculating Moves: For each element, calculate the difference between its initial value and the minimum value. The sum of these differences gives the minimum number of moves.

• Runtime & Storage Complexity: O(n) time complexity, O(1) space complexity

Code

    def minMoves(nums):
    """
    Calculates the minimum number of moves to make all elements in the array equal.

    Args:
        nums: An integer array.

    Returns:
        The minimum number of moves required.
    """

    min_val = min(nums)
    moves = 0
    for num in nums:
        moves += num - min_val
    return moves