# Solving Leetcode Interviews in Seconds with AI: Move Zeroes


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "283" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer array nums, move all 0's to the end of it while maintaining the relative order of the non-zero elements. Note that you must do this in-place without making a copy of the array.   Example 1: Input: nums = [0,1,0,3,12] Output: [1,3,12,0,0] Example 2: Input: nums = [0] Output: [0]    Constraints:  1 <= nums.length <= 104 -231 <= nums[i] <= 231 - 1    Follow up: Could you minimize the total number of operations done?

	# Explanation
	Here's the approach to solve this problem:

*   **Two Pointers:** Use two pointers, `left` and `right`. `left` points to the position where the next non-zero element should be placed, and `right` iterates through the array.
*   **In-Place Swapping:** If `nums[right]` is non-zero, swap `nums[left]` and `nums[right]`, then increment `left`. This ensures that all non-zero elements are moved to the beginning of the array in their original order.
*   **Remaining Elements:** After iterating through the array, all non-zero elements will be at the beginning, and the remaining positions will be filled with zeros automatically because the swapping logic pushes zeros to the end.

*   **Runtime Complexity:** O(n), **Storage Complexity:** O(1)

	
	# Code
	```python
	def move_zeroes(nums):
    """
    Moves all 0's to the end of the array while maintaining the relative order
    of the non-zero elements.

    Args:
        nums: A list of integers.
    """
    left = 0
    for right in range(len(nums)):
        if nums[right] != 0:
            nums[left], nums[right] = nums[right], nums[left]
            left += 1
	```
			
