Introduction

In this blog post, we will explore how to solve the LeetCode problem "1276" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given two integers tomatoSlices and cheeseSlices. The ingredients of different burgers are as follows: Jumbo Burger: 4 tomato slices and 1 cheese slice. Small Burger: 2 Tomato slices and 1 cheese slice. Return [total_jumbo, total_small] so that the number of remaining tomatoSlices equal to 0 and the number of remaining cheeseSlices equal to 0. If it is not possible to make the remaining tomatoSlices and cheeseSlices equal to 0 return []. Example 1: Input: tomatoSlices = 16, cheeseSlices = 7 Output: [1,6] Explantion: To make one jumbo burger and 6 small burgers we need 41 + 26 = 16 tomato and 1 + 6 = 7 cheese. There will be no remaining ingredients. Example 2: Input: tomatoSlices = 17, cheeseSlices = 4 Output: [] Explantion: There will be no way to use all ingredients to make small and jumbo burgers. Example 3: Input: tomatoSlices = 4, cheeseSlices = 17 Output: [] Explantion: Making 1 jumbo burger there will be 16 cheese remaining and making 2 small burgers there will be 15 cheese remaining. Constraints: 0 <= tomatoSlices, cheeseSlices <= 107

Explanation

Here's a solution to the burger problem:

• Approach: We can formulate two equations based on the given information. Let j be the number of jumbo burgers and s be the number of small burgers. Then, we have: 4j + 2s = tomatoSlices and j + s = cheeseSlices. Solving these equations for j and s will give us the answer. We can solve for j in the second equation (j = cheeseSlices - s) and substitute it into the first equation. This gives us 4(cheeseSlices - s) + 2s = tomatoSlices, which simplifies to 4 cheeseSlices - 2s = tomatoSlices. Thus, 2s = 4 cheeseSlices - tomatoSlices, and s = (4 * cheeseSlices - tomatoSlices) / 2. We then solve for j = cheeseSlices - s. We need to check if the calculated values of j and s are non-negative integers to ensure a valid solution.

• Complexity: The runtime complexity is O(1) as the solution involves only arithmetic operations. The storage complexity is also O(1) as we use a fixed number of variables.

Code

    def solve():
    tomatoSlices = int(input())
    cheeseSlices = int(input())
    jumbo = (tomatoSlices - 2 * cheeseSlices) / 2
    small = cheeseSlices - jumbo
    if jumbo >= 0 and small >= 0 and jumbo.is_integer() and small.is_integer():
        print([int(jumbo), int(small)])
    else:
        print([])

solve()