Solving Leetcode Interviews in Seconds with AI: Number of Segments in a String
Introduction
In this blog post, we will explore how to solve the LeetCode problem "434" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given a string s, return the number of segments in the string. A segment is defined to be a contiguous sequence of non-space characters. Example 1: Input: s = "Hello, my name is John" Output: 5 Explanation: The five segments are ["Hello,", "my", "name", "is", "John"] Example 2: Input: s = "Hello" Output: 1 Constraints: 0 <= s.length <= 300 s consists of lowercase and uppercase English letters, digits, or one of the following characters "!@#$%^&*()_+-=',.:". The only space character in s is ' '.
Explanation
Here's the breakdown of the solution:
- Iterate and Count: The core idea is to iterate through the string and increment a counter each time we encounter the beginning of a new segment.
- Segment Start Detection: A new segment starts when we find a non-space character immediately following a space, or when we are at the beginning of the string and the first character is non-space.
Handle Empty Strings: An empty input string should return 0.
Time Complexity: O(n), where n is the length of the string. Space Complexity: O(1).
Code
def countSegments(s: str) -> int:
"""
Counts the number of segments in a string.
A segment is defined as a contiguous sequence of non-space characters.
"""
if not s:
return 0
segment_count = 0
in_segment = False # Flag to track if we're currently inside a segment
for char in s:
if char != ' ':
if not in_segment:
segment_count += 1
in_segment = True
else:
in_segment = False
return segment_count