# Solving Leetcode Interviews in Seconds with AI: Pascal's Triangle


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "118" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer numRows, return the first numRows of Pascal's triangle. In Pascal's triangle, each number is the sum of the two numbers directly above it as shown:    Example 1: Input: numRows = 5 Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]] Example 2: Input: numRows = 1 Output: [[1]]    Constraints:  1 <= numRows <= 30  

	# Explanation
	*   **Iterative Construction:** Build the triangle row by row. Each row is generated using the values from the previous row.
*   **Calculate Intermediate Values:** For each row, the intermediate values (excluding the first and last element which are always 1) are the sum of the two elements directly above in the previous row.

*   **Runtime Complexity:** O(numRows<sup>2</sup>), **Storage Complexity:** O(numRows<sup>2</sup>)

	
	# Code
	```python
	def generate(numRows: int) -> list[list[int]]:
    """
    Generates Pascal's triangle up to numRows.

    Args:
        numRows: The number of rows to generate.

    Returns:
        A list of lists representing Pascal's triangle.
    """
    triangle = []
    for i in range(numRows):
        row = [1] * (i + 1)
        if i > 1:
            for j in range(1, i):
                row[j] = triangle[i - 1][j - 1] + triangle[i - 1][j]
        triangle.append(row)
    return triangle
	```