# Solving Leetcode Interviews in Seconds with AI: Power of Three


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "326" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer n, return true if it is a power of three. Otherwise, return false. An integer n is a power of three, if there exists an integer x such that n == 3x.   Example 1:  Input: n = 27 Output: true Explanation: 27 = 33  Example 2:  Input: n = 0 Output: false Explanation: There is no x where 3x = 0.  Example 3:  Input: n = -1 Output: false Explanation: There is no x where 3x = (-1).    Constraints:  -231 <= n <= 231 - 1    Follow up: Could you solve it without loops/recursion?

	# Explanation
	Here's the breakdown of the approach, complexities, and the Python code:

*   **Approach:**
    *   Handle edge cases: n <= 0. Powers of 3 are always positive.
    *   Find the largest power of 3 that fits within the integer range.
    *   Check if the largest power of 3 is divisible by n. If it is, then n is a power of 3.

*   **Complexity:**
    *   Runtime: O(1), Storage: O(1)

	
	# Code
	```python
	class Solution:
    def isPowerOfThree(self, n: int) -> bool:
        if n <= 0:
            return False
        
        max_power_of_3 = 3**19  # Largest power of 3 within the 32-bit integer range
        return max_power_of_3 % n == 0
	```