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Solving Leetcode Interviews in Seconds with AI: Replace Elements with Greatest Element on Right Side

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2 min read

Introduction

In this blog post, we will explore how to solve the LeetCode problem "1299" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array arr, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1. After doing so, return the array. Example 1: Input: arr = [17,18,5,4,6,1] Output: [18,6,6,6,1,-1] Explanation: - index 0 --> the greatest element to the right of index 0 is index 1 (18). - index 1 --> the greatest element to the right of index 1 is index 4 (6). - index 2 --> the greatest element to the right of index 2 is index 4 (6). - index 3 --> the greatest element to the right of index 3 is index 4 (6). - index 4 --> the greatest element to the right of index 4 is index 5 (1). - index 5 --> there are no elements to the right of index 5, so we put -1. Example 2: Input: arr = [400] Output: [-1] Explanation: There are no elements to the right of index 0. Constraints: 1 <= arr.length <= 104 1 <= arr[i] <= 105

Explanation

Here's an efficient solution to the array replacement problem:

  • Iterate Backwards: Start from the end of the array and move towards the beginning. This allows us to keep track of the greatest element encountered so far.
  • Track Maximum: Maintain a variable to store the maximum value seen to the right.
  • Replace and Update: In each iteration, replace the current element with the maximum value seen so far, and then update the maximum value if the current element is greater.

  • Runtime Complexity: O(n), where n is the length of the array.

  • Storage Complexity: O(1) (in-place modification).

Code

    def replaceElements(arr):
    """
    Replaces each element in the array with the greatest element to its right,
    and the last element with -1.

    Args:
        arr: The input array.

    Returns:
        The modified array.
    """
    max_right = -1
    for i in range(len(arr) - 1, -1, -1):
        temp = arr[i]
        arr[i] = max_right
        max_right = max(max_right, temp)
    return arr

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