Introduction

In this blog post, we will explore how to solve the LeetCode problem "557" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" Example 2: Input: s = "Mr Ding" Output: "rM gniD" Constraints: 1 <= s.length <= 5 * 104 s contains printable ASCII characters. s does not contain any leading or trailing spaces. There is at least one word in s. All the words in s are separated by a single space.

Explanation

Here's the solution, explained and implemented:

• Split and Reverse: Split the input string into a list of words using spaces as delimiters. Reverse each word individually.

• Join: Join the reversed words back together, using spaces to reconstruct the sentence.

• Time & Space Complexity: O(n), where n is the length of the input string. Space complexity is also O(n) due to the creation of the list of words and the reversed string.

Code

    def reverse_words(s: str) -> str:
    """
    Reverses the order of characters in each word within a sentence
    while preserving whitespace and initial word order.
    """
    words = s.split()
    reversed_words = [word[::-1] for word in words]
    return " ".join(reversed_words)