# Solving Leetcode Interviews in Seconds with AI: Richest Customer Wealth


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1672" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has. A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.   Example 1:  Input: accounts = [[1,2,3],[3,2,1]] Output: 6 Explanation: 1st customer has wealth = 1 + 2 + 3 = 6 2nd customer has wealth = 3 + 2 + 1 = 6 Both customers are considered the richest with a wealth of 6 each, so return 6.  Example 2:  Input: accounts = [[1,5],[7,3],[3,5]] Output: 10 Explanation:  1st customer has wealth = 6 2nd customer has wealth = 10  3rd customer has wealth = 8 The 2nd customer is the richest with a wealth of 10. Example 3:  Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17    Constraints:  m == accounts.length n == accounts[i].length 1 <= m, n <= 50 1 <= accounts[i][j] <= 100  

	# Explanation
	Here's the solution to find the wealth of the richest customer:

*   **Calculate wealth per customer:** Iterate through each customer's account list (each row in the `accounts` matrix) and compute the sum of their money across all banks.
*   **Track maximum wealth:** Maintain a variable to keep track of the maximum wealth encountered so far. Update this variable whenever a customer's wealth exceeds the current maximum.
*   **Return maximum wealth:** After processing all customers, return the maximum wealth found.

*   **Runtime Complexity:** O(m\*n), where m is the number of customers and n is the number of banks.
*   **Storage Complexity:** O(1).

	
	# Code
	```python
	def maximumWealth(accounts):
    """
    Calculates the maximum wealth among all customers.

    Args:
        accounts: A list of lists representing the amount of money each customer has in each bank.

    Returns:
        The maximum wealth among all customers.
    """

    max_wealth = 0
    for customer_accounts in accounts:
        customer_wealth = sum(customer_accounts)
        max_wealth = max(max_wealth, customer_wealth)
    return max_wealth
	```