Introduction

In this blog post, we will explore how to solve the LeetCode problem "2236" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given the root of a binary tree that consists of exactly 3 nodes: the root, its left child, and its right child. Return true if the value of the root is equal to the sum of the values of its two children, or false otherwise. Example 1: Input: root = [10,4,6] Output: true Explanation: The values of the root, its left child, and its right child are 10, 4, and 6, respectively. 10 is equal to 4 + 6, so we return true. Example 2: Input: root = [5,3,1] Output: false Explanation: The values of the root, its left child, and its right child are 5, 3, and 1, respectively. 5 is not equal to 3 + 1, so we return false. Constraints: The tree consists only of the root, its left child, and its right child. -100 <= Node.val <= 100

Explanation

Here's the solution, addressing the problem with optimal efficiency:

• Direct Calculation: Access the values of the root, left child, and right child directly.
• Sum Comparison: Check if the root's value equals the sum of its children's values.

• Return Boolean: Return True if the condition holds, False otherwise.

• Runtime Complexity: O(1), Storage Complexity: O(1)

Code

    # Definition for a binary tree node.
class TreeNode:
    def __init__(self, val=0, left=None, right=None):
        self.val = val
        self.left = left
        self.right = right

class Solution:
    def checkTree(self, root: TreeNode) -> bool:
        return root.val == root.left.val + root.right.val