# Solving Leetcode Interviews in Seconds with AI: Rotate String


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "796" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given two strings s and goal, return true if and only if s can become goal after some number of shifts on s. A shift on s consists of moving the leftmost character of s to the rightmost position.  For example, if s = "abcde", then it will be "bcdea" after one shift.    Example 1: Input: s = "abcde", goal = "cdeab" Output: true Example 2: Input: s = "abcde", goal = "abced" Output: false    Constraints:  1 <= s.length, goal.length <= 100 s and goal consist of lowercase English letters.  

	# Explanation
	Here's a breakdown of the solution:

*   **String Concatenation and Substring Check:** The core idea is to concatenate the original string `s` with itself. If `goal` is a rotation of `s`, then `goal` must exist as a substring within this concatenated string.

*   **Length Check:** Before proceeding with the concatenation and substring check, we first confirm if the lengths of the two strings are equal. If they are not, it's impossible for one to be a rotation of the other, so we immediately return `False`.

*   **Optimization:**  Using the `in` operator in Python for substring checking is efficient for this problem's constraint of strings with lengths up to 100.

*   **Runtime and Storage Complexity:**
    *   Runtime: O(N), where N is the length of the strings `s` and `goal`.
    *   Storage: O(N), due to the concatenated string `s + s`.

	
	# Code
	```python
	def rotateString(s: str, goal: str) -> bool:
    """
    Checks if string 'goal' can be obtained by rotating string 's'.
    """
    if len(s) != len(goal):
        return False
    
    concatenated_s = s + s
    return goal in concatenated_s
	```