Solving Leetcode Interviews in Seconds with AI: Sender With Largest Word Count
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2284" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
You have a chat log of n messages. You are given two string arrays messages and senders where messages[i] is a message sent by senders[i]. A message is list of words that are separated by a single space with no leading or trailing spaces. The word count of a sender is the total number of words sent by the sender. Note that a sender may send more than one message. Return the sender with the largest word count. If there is more than one sender with the largest word count, return the one with the lexicographically largest name. Note: Uppercase letters come before lowercase letters in lexicographical order. "Alice" and "alice" are distinct. Example 1: Input: messages = ["Hello userTwooo","Hi userThree","Wonderful day Alice","Nice day userThree"], senders = ["Alice","userTwo","userThree","Alice"] Output: "Alice" Explanation: Alice sends a total of 2 + 3 = 5 words. userTwo sends a total of 2 words. userThree sends a total of 3 words. Since Alice has the largest word count, we return "Alice". Example 2: Input: messages = ["How is leetcode for everyone","Leetcode is useful for practice"], senders = ["Bob","Charlie"] Output: "Charlie" Explanation: Bob sends a total of 5 words. Charlie sends a total of 5 words. Since there is a tie for the largest word count, we return the sender with the lexicographically larger name, Charlie. Constraints: n == messages.length == senders.length 1 <= n <= 104 1 <= messages[i].length <= 100 1 <= senders[i].length <= 10 messages[i] consists of uppercase and lowercase English letters and ' '. All the words in messages[i] are separated by a single space. messages[i] does not have leading or trailing spaces. senders[i] consists of uppercase and lowercase English letters only.
Explanation
Here's the breakdown of the solution:
- Aggregate Word Counts: Iterate through the
messagesandsendersarrays, counting the words in each message and accumulating the word counts for each sender using a dictionary (hash map). - Find Maximum Word Count: Determine the maximum word count among all senders.
Identify Lexicographically Largest Sender: Identify the sender(s) with the maximum word count and return the lexicographically largest among them.
Runtime Complexity: O(n), where n is the number of messages. Storage Complexity: O(n) in the worst case (if all senders are unique).
Code
def largestWordCount(messages, senders):
"""
Finds the sender with the largest word count.
Args:
messages: A list of messages.
senders: A list of senders.
Returns:
The sender with the largest word count.
"""
word_counts = {}
for i in range(len(messages)):
sender = senders[i]
word_count = len(messages[i].split())
word_counts[sender] = word_counts.get(sender, 0) + word_count
max_word_count = 0
for sender in word_counts:
max_word_count = max(max_word_count, word_counts[sender])
largest_senders = []
for sender in word_counts:
if word_counts[sender] == max_word_count:
largest_senders.append(sender)
largest_senders.sort(reverse=True) # Sort lexicographically in descending order
return largest_senders[0]