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Solving Leetcode Interviews in Seconds with AI: Shuffle the Array

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2 min read

Introduction

In this blog post, we will explore how to solve the LeetCode problem "1470" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given the array nums consisting of 2n elements in the form [x1,x2,...,xn,y1,y2,...,yn]. Return the array in the form [x1,y1,x2,y2,...,xn,yn]. Example 1: Input: nums = [2,5,1,3,4,7], n = 3 Output: [2,3,5,4,1,7] Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7]. Example 2: Input: nums = [1,2,3,4,4,3,2,1], n = 4 Output: [1,4,2,3,3,2,4,1] Example 3: Input: nums = [1,1,2,2], n = 2 Output: [1,2,1,2] Constraints: 1 <= n <= 500 nums.length == 2n 1 <= nums[i] <= 10^3

Explanation

Here's a solution to the problem of shuffling an array in the specified manner:

  • Approach:

    • Create a new array to store the shuffled elements.
    • Iterate through the first half of the input array (x1 to xn).
    • For each element xi, append it to the new array, followed by the corresponding yi from the second half of the input array.
  • Complexity:

    • Runtime: O(n), Storage: O(n)

Code

    def shuffle(nums: list[int], n: int) -> list[int]:
    """
    Shuffles an array of the form [x1,x2,...,xn,y1,y2,...,yn] to [x1,y1,x2,y2,...,xn,yn].

    Args:
        nums: The input array.
        n: The number of elements in the first half of the array.

    Returns:
        The shuffled array.
    """
    shuffled_nums = []
    for i in range(n):
        shuffled_nums.append(nums[i])
        shuffled_nums.append(nums[i + n])
    return shuffled_nums

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