# Solving Leetcode Interviews in Seconds with AI: Sign of the Product of an Array


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1822" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Implement a function signFunc(x) that returns:  1 if x is positive. -1 if x is negative. 0 if x is equal to 0.  You are given an integer array nums. Let product be the product of all values in the array nums. Return signFunc(product).   Example 1:  Input: nums = [-1,-2,-3,-4,3,2,1] Output: 1 Explanation: The product of all values in the array is 144, and signFunc(144) = 1  Example 2:  Input: nums = [1,5,0,2,-3] Output: 0 Explanation: The product of all values in the array is 0, and signFunc(0) = 0  Example 3:  Input: nums = [-1,1,-1,1,-1] Output: -1 Explanation: The product of all values in the array is -1, and signFunc(-1) = -1    Constraints:  1 <= nums.length <= 1000 -100 <= nums[i] <= 100  

	# Explanation
	Here's an efficient solution to the problem:

*   **Core Idea:** Instead of calculating the actual product, we only need to track the sign of the product. We can do this by counting the number of negative numbers.
*   **Zero Check:** If any number is zero, the product is zero, so we can return 0 immediately.
*   **Sign Determination:** If the number of negative numbers is even, the product is positive (sign = 1). If the number of negative numbers is odd, the product is negative (sign = -1).

*   **Runtime Complexity:** O(n), where n is the length of the input array. **Storage Complexity:** O(1).

	
	# Code
	```python
	def arraySign(nums):
    """
    Calculates the sign of the product of an array of integers.

    Args:
        nums: A list of integers.

    Returns:
        1 if the product is positive, -1 if negative, and 0 if zero.
    """
    negative_count = 0
    for num in nums:
        if num == 0:
            return 0
        if num < 0:
            negative_count += 1

    if negative_count % 2 == 0:
        return 1
    else:
        return -1
	```