Solving Leetcode Interviews in Seconds with AI: Smallest Even Multiple
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2413" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given a positive integer n, return the smallest positive integer that is a multiple of both 2 and n. Example 1: Input: n = 5 Output: 10 Explanation: The smallest multiple of both 5 and 2 is 10. Example 2: Input: n = 6 Output: 6 Explanation: The smallest multiple of both 6 and 2 is 6. Note that a number is a multiple of itself. Constraints: 1 <= n <= 150
Explanation
Here's the solution to find the smallest positive integer that is a multiple of both 2 and n:
- Key Idea: The problem asks for the Least Common Multiple (LCM) of 2 and n. However, since we know one of the numbers is 2, a simplified approach is sufficient.
- Optimization: If
nis even, it's already a multiple of 2. Otherwise, we just need to multiplynby 2. Direct Calculation: This avoids unnecessary calculations like finding the Greatest Common Divisor (GCD) and then using the LCM = (n1 * n2) / GCD formula.
Complexity: O(1) runtime, O(1) storage.
Code
def smallest_multiple(n: int) -> int:
"""
Given a positive integer n, return the smallest positive integer that is a multiple of both 2 and n.
Example 1:
Input: n = 5
Output: 10
Explanation: The smallest multiple of both 5 and 2 is 10.
Example 2:
Input: n = 6
Output: 6
Explanation: The smallest multiple of both 6 and 2 is 6. Note that a number is a multiple of itself.
Constraints:
1 <= n <= 150
"""
if n % 2 == 0:
return n
else:
return n * 2