# Solving Leetcode Interviews in Seconds with AI: Sort Colors


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "75" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue. We will use the integers 0, 1, and 2 to represent the color red, white, and blue, respectively. You must solve this problem without using the library's sort function.   Example 1:  Input: nums = [2,0,2,1,1,0] Output: [0,0,1,1,2,2]  Example 2:  Input: nums = [2,0,1] Output: [0,1,2]    Constraints:  n == nums.length 1 <= n <= 300 nums[i] is either 0, 1, or 2.    Follow up: Could you come up with a one-pass algorithm using only constant extra space? 

	# Explanation
	Here's the breakdown of the approach and the Python code for the Dutch National Flag algorithm:

*   **Dutch National Flag Algorithm:** This problem is a classic application of the Dutch National Flag algorithm. We maintain three pointers: `low`, `mid`, and `high`. The `low` pointer keeps track of the boundary between the 0s and the 1s, the `mid` pointer iterates through the array, and the `high` pointer keeps track of the boundary between the 2s and the 1s.
*   **In-place Sorting:** The algorithm sorts the array in-place by swapping elements based on their values.
*   **One-Pass:** It achieves the sorting in a single pass through the array.

*   **Runtime & Storage Complexity:** O(n) runtime, O(1) storage.

	
	# Code
	```python
	def sortColors(nums: list[int]) -> None:
    """
    Sorts an array of 0s, 1s, and 2s in-place.

    Args:
        nums: A list of integers representing colors (0, 1, or 2).
    """
    low = 0
    mid = 0
    high = len(nums) - 1

    while mid <= high:
        if nums[mid] == 0:
            nums[low], nums[mid] = nums[mid], nums[low]
            low += 1
            mid += 1
        elif nums[mid] == 1:
            mid += 1
        else:
            nums[mid], nums[high] = nums[high], nums[mid]
            high -= 1
	```