Introduction

In this blog post, we will explore how to solve the LeetCode problem "3152" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

An array is considered special if every pair of its adjacent elements contains two numbers with different parity. You are given an array of integer nums and a 2D integer matrix queries, where for queries[i] = [fromi, toi] your task is to check that subarray nums[fromi..toi] is special or not. Return an array of booleans answer such that answer[i] is true if nums[fromi..toi] is special. Example 1: Input: nums = [3,4,1,2,6], queries = [[0,4]] Output: [false] Explanation: The subarray is [3,4,1,2,6]. 2 and 6 are both even. Example 2: Input: nums = [4,3,1,6], queries = [[0,2],[2,3]] Output: [false,true] Explanation: The subarray is [4,3,1]. 3 and 1 are both odd. So the answer to this query is false. The subarray is [1,6]. There is only one pair: (1,6) and it contains numbers with different parity. So the answer to this query is true. Constraints: 1 <= nums.length <= 105 1 <= nums[i] <= 105 1 <= queries.length <= 105 queries[i].length == 2 0 <= queries[i][0] <= queries[i][1] <= nums.length - 1

Explanation

Here's the solution:

• Precompute Parity: Create an array to store the parity (0 for even, 1 for odd) of each number in nums.
• Check Subarrays: For each query, iterate through the specified subarray using the parity array and check if adjacent elements have different parities.

• Early Exit: If any adjacent pair has the same parity, the subarray is not special, so return False immediately.

• Runtime Complexity: O(N + Q * K), where N is the length of nums, Q is the number of queries, and K is the maximum length of a subarray in the queries.

• Storage Complexity: O(N)

Code

    def solve():
    nums = [int(x) for x in input().split(",")]
    queries_str = input()
    queries_list = queries_str.strip("[]").split("],[")
    queries = []
    for q in queries_list:
        queries.append([int(x) for x in q.split(",")])

    def is_special(subarray):
        if len(subarray) < 2:
            return True
        for i in range(len(subarray) - 1):
            if subarray[i] % 2 == subarray[i+1] % 2:
                return False
        return True

    result = []
    for query in queries:
        from_index = query[0]
        to_index = query[1]
        sub_array = nums[from_index:to_index + 1]
        result.append(is_special(sub_array))

    print(result)

#Get input and process based on the prompt format

solve()