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Solving Leetcode Interviews in Seconds with AI: Split With Minimum Sum

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2 min read

Introduction

In this blog post, we will explore how to solve the LeetCode problem "2578" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given a positive integer num, split it into two non-negative integers num1 and num2 such that: The concatenation of num1 and num2 is a permutation of num. In other words, the sum of the number of occurrences of each digit in num1 and num2 is equal to the number of occurrences of that digit in num. num1 and num2 can contain leading zeros. Return the minimum possible sum of num1 and num2. Notes: It is guaranteed that num does not contain any leading zeros. The order of occurrence of the digits in num1 and num2 may differ from the order of occurrence of num. Example 1: Input: num = 4325 Output: 59 Explanation: We can split 4325 so that num1 is 24 and num2 is 35, giving a sum of 59. We can prove that 59 is indeed the minimal possible sum. Example 2: Input: num = 687 Output: 75 Explanation: We can split 687 so that num1 is 68 and num2 is 7, which would give an optimal sum of 75. Constraints: 10 <= num <= 109

Explanation

Here's the breakdown of the approach and the Python code:

  • High-Level Approach:

    • Convert the number to a string and sort the digits in ascending order. This ensures we use smaller digits in higher places to minimize the sum.
    • Distribute the sorted digits alternately to num1 and num2 strings.
    • Convert num1 and num2 to integers and return their sum.
  • Complexity:

    • Runtime Complexity: O(n log n), where n is the number of digits in num (due to sorting).
    • Storage Complexity: O(n), where n is the number of digits in num (to store the sorted string/list of digits).

Code

    def minimizeSum(num: int) -> int:
    """
    Splits a positive integer into two non-negative integers such that the concatenation
    of the two integers is a permutation of the input integer, and returns the minimum
    possible sum of the two integers.
    """
    s = sorted(str(num))
    num1 = ""
    num2 = ""
    for i in range(len(s)):
        if i % 2 == 0:
            num1 += s[i]
        else:
            num2 += s[i]

    return int(num1) + int(num2)

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