# Solving Leetcode Interviews in Seconds with AI: Subsets


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "78" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer array nums of unique elements, return all possible subsets (the power set). The solution set must not contain duplicate subsets. Return the solution in any order.   Example 1:  Input: nums = [1,2,3] Output: [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]  Example 2:  Input: nums = [0] Output: [[],[0]]    Constraints:  1 <= nums.length <= 10 -10 <= nums[i] <= 10 All the numbers of nums are unique.  

	# Explanation
	*   **Iterative Approach:** Generate subsets iteratively. Start with an empty set. For each number in the input array, create new subsets by adding the number to all existing subsets.
*   **Avoid Duplicates:** Since the input array contains unique elements, adding each element to the existing subsets will inherently avoid duplicate subsets.
*   **Build Subsets Incrementally:** Build the subsets incrementally by processing each element of the input array.

*   **Time Complexity:** O(N * 2<sup>N</sup>), where N is the number of elements in the input array.
*   **Space Complexity:** O(N * 2<sup>N</sup>) to store the power set.

	
	# Code
	```python
	def subsets(nums):
    """
    Generates all possible subsets (the power set) of a given integer array.

    Args:
        nums: An integer array of unique elements.

    Returns:
        A list of lists representing all possible subsets of nums.
    """

    result = [[]]  # Start with an empty set
    for num in nums:
        new_subsets = []
        for subset in result:
            new_subsets.append(subset + [num])  # Add current number to existing subsets
        result.extend(new_subsets)  # Add newly created subsets to the result
    return result
	```