# Solving Leetcode Interviews in Seconds with AI: Sum of Squares of Special Elements


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2778" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given a 1-indexed integer array nums of length n. An element nums[i] of nums is called special if i divides n, i.e. n % i == 0. Return the sum of the squares of all special elements of nums.   Example 1:  Input: nums = [1,2,3,4] Output: 21 Explanation: There are exactly 3 special elements in nums: nums[1] since 1 divides 4, nums[2] since 2 divides 4, and nums[4] since 4 divides 4.  Hence, the sum of the squares of all special elements of nums is nums[1] * nums[1] + nums[2] * nums[2] + nums[4] * nums[4] = 1 * 1 + 2 * 2 + 4 * 4 = 21.    Example 2:  Input: nums = [2,7,1,19,18,3] Output: 63 Explanation: There are exactly 4 special elements in nums: nums[1] since 1 divides 6, nums[2] since 2 divides 6, nums[3] since 3 divides 6, and nums[6] since 6 divides 6.  Hence, the sum of the squares of all special elements of nums is nums[1] * nums[1] + nums[2] * nums[2] + nums[3] * nums[3] + nums[6] * nums[6] = 2 * 2 + 7 * 7 + 1 * 1 + 3 * 3 = 63.     Constraints:  1 <= nums.length == n <= 50 1 <= nums[i] <= 50  

	# Explanation
	Here's the solution to the problem:

*   **High-Level Approach:**
    *   Iterate from 1 to `n` (inclusive).
    *   For each `i`, check if `n` is divisible by `i`.
    *   If it is, add the square of `nums[i-1]` to the running sum.

*   **Complexity Analysis:**
    *   Runtime Complexity: O(n) - We iterate through the array once.
    *   Storage Complexity: O(1) - We only use a constant amount of extra space.

	
	# Code
	```python
	def sum_of_special_elements(nums):
    """
    Calculates the sum of the squares of special elements in the input array.

    Args:
        nums: A 1-indexed integer array.

    Returns:
        The sum of the squares of all special elements.
    """
    n = len(nums)
    total_sum = 0
    for i in range(1, n + 1):
        if n % i == 0:
            total_sum += nums[i - 1] * nums[i - 1]
    return total_sum
	```