# Solving Leetcode Interviews in Seconds with AI: Sum of Two Integers


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "371" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given two integers a and b, return the sum of the two integers without using the operators + and -.   Example 1: Input: a = 1, b = 2 Output: 3 Example 2: Input: a = 2, b = 3 Output: 5    Constraints:  -1000 <= a, b <= 1000  

	# Explanation
	Here's the solution to add two integers without using the + or - operators:

*   **Bitwise Operations:** The core idea is to simulate addition using bitwise operations. `&` (AND) finds the carry bits, `^` (XOR) finds the sum bits (without carry), and left shift (`<<`) moves the carry bits to the next position.

*   **Iteration:** The process is repeated until there are no more carry bits to add.

*   **Handling Negative Numbers:** The code handles negative numbers using the concept of two's complement. A mask is used to ensure the result stays within the 32-bit integer range to mimic the behavior of standard integer addition in many programming environments.

*   **Runtime & Storage Complexity:** O(1) - The number of iterations depends on the number of carry bits, which is bounded by the size of the integers. The space complexity is O(1) as it uses a fixed number of variables.

	
	# Code
	```python
	def getSum(a: int, b: int) -> int:
    """
    Calculates the sum of two integers without using the + or - operators.
    """
    mask = 0xFFFFFFFF  # Mask for 32-bit integers

    while (b & mask) > 0:
        carry = (a & b) << 1
        a = a ^ b
        b = carry

    return (a & mask) if b > 0 else a
	```