Solving Leetcode Interviews in Seconds with AI: Thousand Separator
Introduction
In this blog post, we will explore how to solve the LeetCode problem "1556" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given an integer n, add a dot (".") as the thousands separator and return it in string format. Example 1: Input: n = 987 Output: "987" Example 2: Input: n = 1234 Output: "1.234" Constraints: 0 <= n <= 231 - 1
Explanation
Here's a breakdown of the approach, followed by the Python code:
- Convert to String and Iterate Backwards: Convert the integer to its string representation. Iterate through the string from right to left (least significant digit to most significant digit).
- Insert Separators: Insert a dot (".") after every three digits.
Handle Leading Dot: Remove any leading dot that might result from the insertion process.
Runtime Complexity: O(N), where N is the number of digits in the input integer. Storage Complexity: O(N)
Code
def thousand_separator(n: int) -> str:
"""
Given an integer n, add a dot (".") as the thousands separator and return it in string format.
Example 1:
Input: n = 987
Output: "987"
Example 2:
Input: n = 1234
Output: "1.234"
Constraints:
0 <= n <= 231 - 1
"""
s = str(n)
res = ""
count = 0
for i in range(len(s) - 1, -1, -1):
res = s[i] + res
count += 1
if count == 3 and i != 0:
res = "." + res
count = 0
return res