Introduction

In this blog post, we will explore how to solve the LeetCode problem "3379" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an integer array nums that represents a circular array. Your task is to create a new array result of the same size, following these rules: For each index i (where 0 <= i < nums.length), perform the following independent actions: If nums[i] > 0: Start at index i and move nums[i] steps to the right in the circular array. Set result[i] to the value of the index where you land. If nums[i] < 0: Start at index i and move abs(nums[i]) steps to the left in the circular array. Set result[i] to the value of the index where you land. If nums[i] == 0: Set result[i] to nums[i]. Return the new array result. Note: Since nums is circular, moving past the last element wraps around to the beginning, and moving before the first element wraps back to the end. Example 1: Input: nums = [3,-2,1,1] Output: [1,1,1,3] Explanation: For nums[0] that is equal to 3, If we move 3 steps to right, we reach nums[3]. So result[0] should be 1. For nums[1] that is equal to -2, If we move 2 steps to left, we reach nums[3]. So result[1] should be 1. For nums[2] that is equal to 1, If we move 1 step to right, we reach nums[3]. So result[2] should be 1. For nums[3] that is equal to 1, If we move 1 step to right, we reach nums[0]. So result[3] should be 3. Example 2: Input: nums = [-1,4,-1] Output: [-1,-1,4] Explanation: For nums[0] that is equal to -1, If we move 1 step to left, we reach nums[2]. So result[0] should be -1. For nums[1] that is equal to 4, If we move 4 steps to right, we reach nums[2]. So result[1] should be -1. For nums[2] that is equal to -1, If we move 1 step to left, we reach nums[1]. So result[2] should be 4. Constraints: 1 <= nums.length <= 100 -100 <= nums[i] <= 100

Explanation

• Iterate through the input array nums.
  • For each element, calculate the destination index based on its value (positive or negative). Handle the circular array nature using the modulo operator.
  • Store the value at the destination index in the corresponding position of the result array.

• Runtime Complexity: O(n), where n is the length of the input array nums.
• Storage Complexity: O(n), for storing the result array.

Code

    def circular_array_loop(nums):
    """
    Calculates a new array based on movements in a circular array.

    Args:
        nums: An integer array representing a circular array.

    Returns:
        A new array result of the same size.
    """
    n = len(nums)
    result = [0] * n

    for i in range(n):
        if nums[i] > 0:
            destination_index = (i + nums[i]) % n
            result[i] = nums[destination_index]
        elif nums[i] < 0:
            destination_index = (i + nums[i]) % n
            result[i] = nums[destination_index]
        else:
            result[i] = nums[i]

    return result