Solving Leetcode Interviews in Seconds with AI: Unique Paths
Introduction
In this blog post, we will explore how to solve the LeetCode problem "62" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
There is a robot on an m x n grid. The robot is initially located at the top-left corner (i.e., grid[0][0]). The robot tries to move to the bottom-right corner (i.e., grid[m - 1][n - 1]). The robot can only move either down or right at any point in time. Given the two integers m and n, return the number of possible unique paths that the robot can take to reach the bottom-right corner. The test cases are generated so that the answer will be less than or equal to 2 * 109. Example 1: Input: m = 3, n = 7 Output: 28 Example 2: Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Down -> Down 2. Down -> Down -> Right 3. Down -> Right -> Down Constraints: 1 <= m, n <= 100
Explanation
- Combinatorial Approach: The problem can be reframed as finding the number of ways to choose (m-1) down moves (or n-1 right moves) from a total of (m+n-2) moves. This is a combination problem, specifically (m+n-2) choose (m-1).
- Optimized Combination Calculation: We can compute the combination efficiently using the formula C(n, k) = n! / (k! * (n-k)!). To avoid potential overflow issues with large factorials, we calculate the combination iteratively, canceling out common factors.
- Utilize Smaller Value: To optimize calculations, always choose the smaller value between
m-1andn-1askfor calculating combinations i.e.C(n, k) = C(n, n-k).
- Runtime Complexity: O(min(m, n)), Storage Complexity: O(1)
Code
def uniquePaths(m: int, n: int) -> int:
"""
Calculates the number of unique paths from the top-left corner to the
bottom-right corner of an m x n grid, where the robot can only move down or right.
Args:
m: The number of rows in the grid.
n: The number of columns in the grid.
Returns:
The number of unique paths.
"""
N = m + n - 2
k = min(m - 1, n - 1) # Number of down or right moves needed
result = 1
for i in range(k):
result = result * (N - i) // (i + 1)
return result