Introduction

In this blog post, we will explore how to solve the LeetCode problem "1037" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array points where points[i] = [xi, yi] represents a point on the X-Y plane, return true if these points are a boomerang. A boomerang is a set of three points that are all distinct and not in a straight line. Example 1: Input: points = [[1,1],[2,3],[3,2]] Output: true Example 2: Input: points = [[1,1],[2,2],[3,3]] Output: false Constraints: points.length == 3 points[i].length == 2 0 <= xi, yi <= 100

Explanation

Here's a breakdown of the solution and the code:

• Approach:

  • Check if all three points are distinct. If any two points are the same, it's not a boomerang.
  • Calculate the slope between the first two points and the first and third points. If the slopes are different, the points are not collinear (not on the same straight line). Note: handle cases where the x coordinates are the same to avoid division by zero when calculating the slope.

• Complexity:

  • Runtime: O(1), Storage: O(1) - the code performs a fixed number of calculations and uses a fixed amount of memory, regardless of input size (due to the constraint of only 3 points).

Code

    def isBoomerang(points):
    """
    Determines if three points form a boomerang.

    Args:
        points: A list of three points, where each point is a list [x, y].

    Returns:
        True if the points form a boomerang, False otherwise.
    """

    # Check if any two points are the same
    if points[0] == points[1] or points[0] == points[2] or points[1] == points[2]:
        return False

    # Check if the points are collinear (on the same line)
    x1, y1 = points[0]
    x2, y2 = points[1]
    x3, y3 = points[2]

    # Calculate the slope between (x1, y1) and (x2, y2)
    # Calculate the slope between (x1, y1) and (x3, y3)

    # If x1 == x2, the slope is infinite, so check if x1 == x3
    if x1 == x2:
        return x1 != x3

    # If x1 == x3, the slope is infinite, so check if x1 == x2
    if x1 == x3:
        return x1 != x2

    slope1 = (y2 - y1) / (x2 - x1)
    slope2 = (y3 - y1) / (x3 - x1)

    return slope1 != slope2