Introduction

In this blog post, we will explore how to solve the LeetCode problem "1518" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

There are numBottles water bottles that are initially full of water. You can exchange numExchange empty water bottles from the market with one full water bottle. The operation of drinking a full water bottle turns it into an empty bottle. Given the two integers numBottles and numExchange, return the maximum number of water bottles you can drink. Example 1: Input: numBottles = 9, numExchange = 3 Output: 13 Explanation: You can exchange 3 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 9 + 3 + 1 = 13. Example 2: Input: numBottles = 15, numExchange = 4 Output: 19 Explanation: You can exchange 4 empty bottles to get 1 full water bottle. Number of water bottles you can drink: 15 + 3 + 1 = 19. Constraints: 1 <= numBottles <= 100 2 <= numExchange <= 100

Explanation

Here's the breakdown of the solution:

• Simulate the process: Keep track of the number of full bottles and empty bottles. In each step, drink all full bottles, update the number of empty bottles, and exchange empty bottles for full bottles as much as possible.
• Iterative Calculation: Repeat the exchange process until the number of empty bottles is less than the required exchange amount.

• Accumulate Drunk Bottles: Sum up the number of bottles drunk in each step to get the final result.

• Runtime Complexity: O(log_exchange numBottles). Storage Complexity: O(1).

Code

    class Solution:
    def numWaterBottles(self, numBottles: int, numExchange: int) -> int:
        drunk_bottles = numBottles
        empty_bottles = numBottles

        while empty_bottles >= numExchange:
            new_bottles = empty_bottles // numExchange
            drunk_bottles += new_bottles
            empty_bottles = empty_bottles % numExchange + new_bottles

        return drunk_bottles